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Is their a good per sqft per inch price?

Discussion in 'Commercial Snow Removal' started by SweeetLandscpng, Nov 5, 2006.

  1. SweeetLandscpng

    SweeetLandscpng Junior Member
    Messages: 2

    Does anyone have a price for a per square foot/per inch that seems to make them money and keep the phones ringing most of my pricing based on comparative lots ANY IDEAS LET ME KNOW PLEASE :D
  2. Mick

    Mick PlowSite.com Veteran
    from Maine
    Messages: 5,546

    How about per acre for lots? Should be about an hour. So, since there is 43,560 sq ft in one acre, divide your hourly rate by that and get your per sq ft rate. If a general hourly rate is $125, then I get $0.287 per sq ft for an acre lot. Then, for a 50'x60' area, it would be $8.61. A 10'x25' driveway would be 72 cents.

    That's why I'm not a fan of sq ft pricing. It doesn't make sense as it can't be applied consistently.

    Per inch?? You must be kidding.
  3. Duracutter

    Duracutter Senior Member
    from Canada
    Messages: 200

    Ah yes, glorious snow. Please take me to ur ledder, I require price per square millimeter...:confused:
  4. hesko1

    hesko1 Member
    Messages: 45

    That's why I'm not a fan of sq ft pricing. It doesn't make sense as it can't be applied consistently . Redo your math! The only way to survive in this business is to know what your numbers are!
    Last edited: Nov 5, 2006
  5. john boardman

    john boardman Member
    Messages: 44

    How about .0025 per square foot + 25.00 service call or trip fee. So a residential drive that is 20X50=1000sq ft 1000 X .0025 = 2.50 + 25.00 fee = 27.50 or 40,000 sq ft lot X .0025 = 100.00 + 25.00 trip fee = 125.00 then adjust the service fee for problems (difficult pushes or any shoveling of walks) This .0025 would be for 2-4" of snow and would increase with more snow accordingly. Just a suggestion it's the math I'm using for a starting point. Or if a residential drive is worth more to you then increase the service fee for residentials to get the most money you can get for your time and still be competative in your area.
    Last edited: Nov 6, 2006
  6. Mick

    Mick PlowSite.com Veteran
    from Maine
    Messages: 5,546

    Funny, but I'm agreeing to a point - forget the sq ft stuff and stick with the "service fee" and the variables you mentioned. The sq ft charge only complicates the issue.
    The customer only wants to know "how much". Telling them "It'll be $25" is easier for them to comprehend than figuring how many sq ft and adding it to... and, then .... Not only that, there could be real issues in measuring, like driveways with poorly defined shoulders, long lanes etc. For a 50'x60' lot, for example, that's 120 sq ft if you had a dispute of 6" on each side.
  7. Mick

    Mick PlowSite.com Veteran
    from Maine
    Messages: 5,546

    I agree:

    $125 / 43560 (sq ft per acre) = .002869605 (per sq ft)

    .002869605 x 3,000 (50x60) = $8.6088 (rounded to $8.61)
    .002869605 x 250 (10x25) = 0.71740125 (rounded to .72)

    ( I see - on the original reply, I had 286... as a fraction of dollar, when I meant a fraction of a cent. The results were correct, though so likely it was simply not getting the zeros from calculator to here.)
    Last edited: Nov 6, 2006
  8. Mark Oomkes

    Mark Oomkes PlowSite Fanatic
    Messages: 10,425

    I was thinking of trying a by the snowflake pricing method, anybody have any good way of estimating how many snowflakes per inch per acre?

    OK, enough of the sarcasm. Another point against square foot pricing, what say I have one lot that is an acre and no obstacles, so an experienced operator with a pickup should be able to get it plowed in about 45 minutes at the most with an 8' plow.

    The next lot is also an acre, but there are islands and handicap spaces with curbing and signs all over this lot. How do you figure the price on this one? Same experienced plower, same truck.

    I'll give you a hint, you are not selling square feet. What are you selling when you have a limited amount of TIME to perform the service?
  9. jcesar

    jcesar Senior Member
    from Mi
    Messages: 492

    Hey Mark.....
    I know I know:redbounce purplebou
    The correct answer is .......Time.
    I think I am Right. am I right? Or
    Am I right? or
    Am I Right?
    By the snowflake, would be 2,34567 snowflakes in an inch, divided by the square root of pie r squared, times 2 ............ I think I am wrong, but it should be 12!!!!!
    Anyways, don't do the per foot or inch. Bid it for your time, and make money.
  10. LLM Ann Arbor

    LLM Ann Arbor Senior Member
    Messages: 876

    Heres my math. Take what you would charge and then cut it in half, becayse the next guy that bid it or the guy right ahead of you surely bid it at 50% reasonable rate.

    This business is a joke.